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b is a multiple of positive integer a.
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14 May 2017, 04:57
14 May 2017, 04:57
Expert Reply
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Question Stats:
81% (00:33) correct
18% (00:39) wrong based on 104 sessions
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b is a multiple of positive integer a.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The ratio of a to b |
\(\frac{1}{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Drill 1
Question: 6
Page: 337
Question: 6
Page: 337
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Re: b is a multiple of positive integer a.
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16 May 2017, 12:03
16 May 2017, 12:03
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sandy wrote:
b is a multiple of positive integer a.
Quantity A |
Quantity B |
The ratio of a to b |
\(\frac{1}{2}\) |
Let's test some values...
Given: b is a multiple of positive integer a
So, it could be the case that a = 3 and b = 6 (since 6 is a multiple of 3)
We get:
Quantity A: ratio = 3/6 = 1/2
Quantity B: 1/2
In this case the two quantities are EQUAL
It could also be the case that a = 3 and b = 3 (since 3 is a multiple of 3)
We get:
Quantity A: ratio = 3/3 = 1
Quantity B: 1/2
In this case Quantity A IS GREATER
Answer:
Show: ::
D
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Re: b is a multiple of positive integer a.
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04 Jun 2017, 14:50
04 Jun 2017, 14:50
Expert Reply
Explanation
Because you have variables, make your set-up on your scratch paper. Plug in different values for a and b.
First, try 2 and 4: \(\frac{2}{4}\) reduces to \(\frac{1}{2}\), making the quantities equal.
Eliminate choices (A) and (B).
Next, try 2 and 6. \(\frac{2}{6}\) reduces to \(\frac{1}{3}\), which is less than . Quantity B is now greater, so eliminate choice (C). You’re left with choice D.
Because you have variables, make your set-up on your scratch paper. Plug in different values for a and b.
First, try 2 and 4: \(\frac{2}{4}\) reduces to \(\frac{1}{2}\), making the quantities equal.
Eliminate choices (A) and (B).
Next, try 2 and 6. \(\frac{2}{6}\) reduces to \(\frac{1}{3}\), which is less than . Quantity B is now greater, so eliminate choice (C). You’re left with choice D.
