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In the figure above, the area of ABC is 35. What is the
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08 Oct 2017, 00:46
08 Oct 2017, 00:46
Expert Reply
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Question Stats:
95% (01:00) correct
4% (01:13) wrong based on 48 sessions
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#GREpracticequestion In the figure above, the area of ABC is 35. What is the.jpg [ 11.06 KiB | Viewed 5749 times ]
In the figure above, the area of \(\triangle\) ABC is 35. What is the length of DC?
enter your value
Show: :: OA
8
Re: In the figure above, the area of ABC is 35. What is the
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09 Oct 2017, 01:50
09 Oct 2017, 01:50
1
Carcass wrote:
Attachment:
triangle.jpg
In the figure above, the area of \(\triangle\) ABC is 35. What is the length of DC?
enter your value
Show: :: OA
8
Given
\(\triangle\) ABC = 35
I.e \(\frac{1}{2} * BC * 7 = 35\)
or BC = 10
Now in \(\triangle\) BCD,
\(DC^2= \sqrt{(10^2 - 6^2)}\) = 64
or DC = 8
Re: In the figure above, the area of ABC is 35. What is the
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09 Oct 2017, 07:28
09 Oct 2017, 07:28
Another way to solve it is to notice that one leg of BCD is 6 and the hypotenuse is 10, and given that the triangle is a right triangle, we can use the Pitagorean triplet 3:4:5, where each of the sides is doubled. Indeed, in this case we would have 6:x:10 and x = 8.
