Last visit was: 31 Oct 2024, 15:51 It is currently 31 Oct 2024, 15:51

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 29853
Own Kudos [?]: 36044 [9]
Given Kudos: 25902
Send PM
Most Helpful Community Reply
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12167 [7]
Given Kudos: 136
Send PM
General Discussion
avatar
Director
Director
Joined: 03 Sep 2017
Posts: 518
Own Kudos [?]: 699 [0]
Given Kudos: 0
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 29853
Own Kudos [?]: 36044 [0]
Given Kudos: 25902
Send PM
Re: n is an integer. [#permalink]
Expert Reply
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT \(2n + 1\) but it is (if you notice very carefully) that 2 (in the first quantity) is \(2^{n+1}\)
avatar
Director
Director
Joined: 03 Sep 2017
Posts: 518
Own Kudos [?]: 699 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
1
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT \(2n + 1\) but it is (if you notice very carefully) that 2 (in the first quantity) is \(2^{n+1}\)


Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as \(2^{n+1} = 2n+2\). Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
avatar
Intern
Intern
Joined: 12 Nov 2017
Posts: 30
Own Kudos [?]: 53 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
Shouldnt the answer be "B" ?
becuase A is always -1 and B is always 1
Carcass wrote:

This question is part of GREPrepClub - The Questions Vault Project



n is an integer.

Quantity A
Quantity B
\((-1)^2^^{n+1}\)
\((1)^n\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
avatar
Intern
Intern
Joined: 12 Nov 2017
Posts: 30
Own Kudos [?]: 53 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
Thank you now I get it
IlCreatore wrote:
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT \(2n + 1\) but it is (if you notice very carefully) that 2 (in the first quantity) is \(2^{n+1}\)


Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as \(2^{n+1} = 2n+2\). Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
avatar
Intern
Intern
Joined: 14 Jun 2018
Posts: 36
Own Kudos [?]: 13 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
Carcass wrote:

This question is part of GREPrepClub - The Questions Vault Project



n is an integer.

Quantity A
Quantity B
\((-1)^{2}^{n+1}\)
\((1)^n\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Carcass, you are still writing it (D)? I agree that it's (C).
avatar
Intern
Intern
Joined: 15 May 2018
Posts: 38
Own Kudos [?]: 11 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
Carcass wrote:

This question is part of GREPrepClub - The Questions Vault Project



n is an integer.

Quantity A
Quantity B
\((-1)^{2}^{n+1}\)
\((1)^n\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

ANswer IS D
avatar
Active Member
Active Member
Joined: 27 Aug 2019
Posts: 59
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
1
IlCreatore wrote:
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT \(2n + 1\) but it is (if you notice very carefully) that 2 (in the first quantity) is \(2^{n+1}\)


Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as \(2^{n+1} = 2n+2\). Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?


You did right in considering the exponent as 2n+2. Since n is an integer, if for example you consider n=-1, then 2n+2 = 0. Then answer A would be equal to answer B. Thus you cannot get to a definite conclusion. Answer is D.

Regards
Intern
Intern
Joined: 13 Nov 2018
Posts: 36
Own Kudos [?]: 25 [0]
Given Kudos: 24
Send PM
Re: n is an integer. [#permalink]
1
since n is a integer. if the n =1 then the value in A is -1 while in B is 1. if the n=2 then the both values are equal.
So the answer is D.
avatar
Intern
Intern
Joined: 24 Oct 2020
Posts: 15
Own Kudos [?]: 17 [2]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
2
I believe the answer is C.

the question is (-1) to the power of 2 to the power of (n+1)

So to solve first we have to designate different values for n (integer) including +ve and -ve values.

if n = +1 => the last power will be (1+1). so it will be (-1) to the power of (2) to the power of (2) which is (-1) to the power of 4 and thus equals to 1.
Answer is C

if n = -1 => the last power will be (0). So it will be (-1) to the power of (2) to the power of (0), which is (-1) to the power of (0) which is also equal to 1.
Answer is C

if n = 2 => the last power will be (3). So it will be (-1) to the power of (2) to the power of (3), which is (-1) to the power of (6) which is also equal to 1.
Answer is C.

if n=-2 => the last power will be (-1). So it will be (-1) to the power of (2) to the power of (-1), which is (-1) to the power of (-2), which is synonymous to the 1/(-1)^2 which equals to 1 eventually.

Answer is still C.

I think the idea over here in this question is that we have two exponents, last of them is n+1, whatever value we put its going to be multiplied by (2) and thus becoming even, although it might be negative (the -ve sign in the exponent signals a reciprocal) the reciprocal of 1 is going to be 1. So since the value - or reciprocal- of (-1)^even it is always going to give us a positive signed 1.

Thus the answer MUST be C.
Verbal Expert
Joined: 18 Apr 2015
Posts: 29853
Own Kudos [?]: 36044 [0]
Given Kudos: 25902
Send PM
Re: n is an integer. [#permalink]
Expert Reply
Question of the day on Instagram. Promoted

Thanks!!!
Intern
Intern
Joined: 02 Jul 2021
Posts: 4
Own Kudos [?]: 10 [3]
Given Kudos: 2
Send PM
Re: n is an integer. [#permalink]
3
Since its (-1)^(2^(n+1)) and n is an integer, if we take n to be say -2
the equation would become
(-1)^(2^(-1))
= (-1)^(1/2)
= sqrt(-1)
which is not defined hence answer is D
Intern
Intern
Joined: 08 Aug 2022
Posts: 49
Own Kudos [?]: 36 [1]
Given Kudos: 98
Send PM
Re: n is an integer. [#permalink]
1
I found this problem easiest to considering some scenarios that might yield interesting results.

n=1 --> A = 1, B = 1 --> A=B
n=0 --> A = 1, B = 1 --> A=B
n=-1 --> A = -1, B = 1 --> A<B

Hence, the answer is D.
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5000
Own Kudos [?]: 73 [0]
Given Kudos: 0
Send PM
Re: n is an integer. [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: n is an integer. [#permalink]
Moderators:
GRE Instructor
77 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
222 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne