Carcass wrote:
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The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?
enter your value in metersHere the two sides AB and AC are equal, so we can conclude that
the
△ABC is isosceles.
Now the minimum length from A to BC will be the perpendicular line.
Since the
△ABC is isosceles and perpendicular line from A to BC will meet at the midpoint D (as shown in the figure)
Now consider the
△ABDAB = 100 , BD =80 and we need to find AD
Using Pythagoras theorem
AD =
√(10000−6400) = 60
or we can see that the sides of
△ABD are in the ratio 3:4:5
= 60:80:100
Ans = 60
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