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The height of a rectangular 3D figure is increased by p per
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05 Jun 2017, 02:36
05 Jun 2017, 02:36
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Question Stats:
67% (01:23) correct
32% (01:27) wrong based on 137 sessions
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The height of a rectangular 3D figure is increased by p percent, its depth is decreased by p percent and its width is unchanged.
Quantity A |
Quantity B |
The volume of the new 3D figure if p = 20 |
The volume of the new 3D figure if p = 40 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: The height of a rectangular 3D figure is increased by p per
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11 Oct 2017, 05:41
11 Oct 2017, 05:41
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The volume of a 3d rectangular figure is height*depth*width.
Then, if p = 20, the volume is (1+0.02)*h*(1-0.02)*d*w
If p= 40, instead, the volume is (1+0.04)*h*(1-0.04)*d*w
Simplifying the two expression getting rid of the letters, we remain with the comparison between 1.2*0.8 = 0.96 and 1.4*0.6 = 0.84.
Quantity A is greater!
Then, if p = 20, the volume is (1+0.02)*h*(1-0.02)*d*w
If p= 40, instead, the volume is (1+0.04)*h*(1-0.04)*d*w
Simplifying the two expression getting rid of the letters, we remain with the comparison between 1.2*0.8 = 0.96 and 1.4*0.6 = 0.84.
Quantity A is greater!
Re: The height of a rectangular 3D figure is increased by p per
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10 Aug 2019, 03:31
10 Aug 2019, 03:31
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QA:
1.2*0.8*LBH
QB:
1.4*0.6*LBH
QA is greater
1.2*0.8*LBH
QB:
1.4*0.6*LBH
QA is greater
