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x + y < z
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21 May 2019, 02:48
21 May 2019, 02:48
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Question Stats:
86% (01:03) correct
13% (01:17) wrong based on 101 sessions
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\(x + y < z\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(2x-z\) |
\(-y\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: x + y < z
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21 May 2019, 07:02
21 May 2019, 07:02
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Carcass wrote:
\(x + y < z\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(2x-z\) |
\(-y\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Given:
Quantity A: 2x - z
Quantity B: -y
Let's try to make the quantities RESEMBLE the given inequality: x + y < z
Add y both quantities to get:
Quantity A: 2x - z + y
Quantity B: 0
Add z both quantities to get:
Quantity A: 2x + y
Quantity B: z
SO CLOSE!!
If Quantity A were x + y (rather than 2x + y), we'd be able to conclude that Quantity B is bigger (since we know that x + y < z)
HOWEVER, this is not the case.
Given all of this, it seems likely that the correct answer might be D.
So, let's test some possible values of x, y and z (that satisfies the restriction that x + y < z)
case i: x = 3, y = 1 and z = 5 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 5
In this case, Quantity A is greater
case ii: x = 3, y = 1 and z = 500 (this satisfies the inequality x + y < z)
We get:
Quantity A: 2x + y = 2(3) + 1 = 7
Quantity B: z = 500
In this case, Quantity B is greater
Answer: D
Cheers,
Brent
Re: x + y < z
[#permalink]
21 May 2019, 07:08
21 May 2019, 07:08
1
suppose x=3, y=2 and z=6
so 3+2<6
then 2*x-z
A=2*3-6=0 where B=-2
again suppose x=3 y=-2 and z=6
A=6-6=0 but B=2
clearly D is the answer.
so 3+2<6
then 2*x-z
A=2*3-6=0 where B=-2
again suppose x=3 y=-2 and z=6
A=6-6=0 but B=2
clearly D is the answer.
