sandy wrote:
With 4 identical servers working at a constant rate, a new Internet search provider processes 9,600 search requests per hour. If the search provider adds 2 more identical servers, and server work rate never varies, the search provider can process 216,000 search requests in how many hours?
(A) 15
(B) 16
(C) 18
(D) 20
(E) 24
Here,
4 identical servers work at a constant rate, a new internet search provider processes 9,600 search requests per hour.
1 server work at a rate = \(\frac{9600}{4}\) = 2400 search request per hour.
Now we know
Work = TIme * Rate * No. of units
i.e 216000 = Time * 2400 * 6
Time = \(\frac{(216,000)}{(2400*6)}\) = 15hours
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