GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 25Crafting an Impactful Resume: Balancing Detail with Brevity
10:00 AM EDT
-10:30 AM EDT
Showcase your achievements through impactful storytelling! Get ready for an LIVE session on April 25, Learn how to craft compelling narratives on your resume that resonate with admission committees.
Apr 26Get a Top GRE Score with Target Test Prep
12:00 PM EDT
-01:00 PM EDT
The Target Test Prep course represents a quantum leap forward in GRE preparation, a radical reinterpretation of the way that students should study. In fact, more and more Target Test Prep students are scoring 329 and above on the GRE.
A border of uniform width is placed around a rectangular pho
[#permalink]
20 May 2020, 08:43
20 May 2020, 08:43
1
Expert Reply
11
Bookmarks
00:00
Question Stats:
43% (02:41) correct
56% (02:29) wrong based on 200 sessions
Hide Show timer Statistics
A border of uniform width is placed around a rectangular photograph that measures 8 inches by 10 inches. If the area of the border is 144 square inches, what is the width of the border, in inches?
(A) 3
(B) 4
(C) 6
(D) 8
(E) 9
(A) 3
(B) 4
(C) 6
(D) 8
(E) 9
Re: A border of uniform width is placed around a rectangular pho
[#permalink]
22 May 2020, 07:19
22 May 2020, 07:19
5
1
The quickest way to solve this problem is to plug in the options
area of photograph (inner rectangle) = 8*10 = 80
area of the border (outer - inner) = 144
area of border = area of outer rectangle - area of inner rectangle
plugging in option A as possible width of the border, the dimensions of the outer rectangle become, 8+3+3= 14 and 10+3+3=16 (equal width on either side)
area of outer rectangle = 14*16=224
area of border = 224-80=144 which satisfies the question
Answer is A.
area of photograph (inner rectangle) = 8*10 = 80
area of the border (outer - inner) = 144
area of border = area of outer rectangle - area of inner rectangle
plugging in option A as possible width of the border, the dimensions of the outer rectangle become, 8+3+3= 14 and 10+3+3=16 (equal width on either side)
area of outer rectangle = 14*16=224
area of border = 224-80=144 which satisfies the question
Answer is A.
General Discussion
Re: A border of uniform width is placed around a rectangular pho
[#permalink]
20 May 2020, 08:43
20 May 2020, 08:43
1
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
