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An investor purchased a share of non-dividend-paying stock for p dolla
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31 Mar 2021, 21:26
31 Mar 2021, 21:26
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An investor purchased a share of non-dividend-paying stock for p dollars on Monday. For a certain number of days, the value of the share increased by r percent per day. After this period of constant increase, the value of the share decreased the next day by q dollars and the investor decided to sell the share at the end of that day for v dollars, which was the value of the share at that time. How many working days after the investor bought the share was the share sold, if \(r=100(\sqrt{\frac{v+q}{p}}-1)\)
A. Two working days later.
B. Three working days later.
C. Four working days later.
D. Five working days later.
E. Six working days later.
A. Two working days later.
B. Three working days later.
C. Four working days later.
D. Five working days later.
E. Six working days later.
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Re: An investor purchased a share of non-dividend-paying stock for p dolla
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31 Mar 2021, 22:49
31 Mar 2021, 22:49
3
GeminiHeat wrote:
An investor purchased a share of non-dividend-paying stock for p dollars on Monday. For a certain number of days, the value of the share increased by r percent per day. After this period of constant increase, the value of the share decreased the next day by q dollars and the investor decided to sell the share at the end of that day for v dollars, which was the value of the share at that time. How many working days after the investor bought the share was the share sold, if \(r=100(\sqrt{\frac{v+q}{p}}-1)\)
A. Two working days later.
B. Three working days later.
C. Four working days later.
D. Five working days later.
E. Six working days later.
A. Two working days later.
B. Three working days later.
C. Four working days later.
D. Five working days later.
E. Six working days later.
GeminiHeat
Good Question!
\(r = 100(\sqrt{\frac{v+q}{p}}-1)\)
\(r = 100(\sqrt{\frac{v+q}{p}}) - 100\)
\(r + 100 = 100(\sqrt{\frac{v+q}{p}})\)
\(\frac{(r + 100)}{100} = (\sqrt{\frac{v+q}{p}})\)
\(1 + \frac{r}{100} = (\sqrt{\frac{v+q}{p}})\)\
Squaring both sides;
\((1 + \frac{r}{100})^2 = \frac{v + q}{p}\)
\(v = p(1 + \frac{r}{100})^2 - q\)
Since the expression \((1 + \frac{r}{100})^2\) has a power of \(2\), the value must have increased for \(2\) days and then decreased on another day!
Therefore, a total of \(3\) days
Hence, option B
Hence, option B
An investor purchased a share of non-dividend-paying stock for p dolla
[#permalink]
05 Apr 2021, 05:34
05 Apr 2021, 05:34
1
these are gre questions....i mean they are tough ......compare what i seen in actual gre exams!!!
