Last visit was: 25 Apr 2024, 05:57 It is currently 25 Apr 2024, 05:57

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 28634
Own Kudos [?]: 33116 [6]
Given Kudos: 25175
Send PM
Manager
Manager
Joined: 06 Nov 2020
Posts: 85
Own Kudos [?]: 69 [0]
Given Kudos: 101
Send PM
Senior Manager
Senior Manager
Joined: 03 Dec 2020
Posts: 440
Own Kudos [?]: 59 [0]
Given Kudos: 68
Send PM
Retired Moderator
Joined: 09 Jan 2021
Posts: 576
Own Kudos [?]: 837 [3]
Given Kudos: 194
GRE 1: Q167 V156
GPA: 4
WE:Analyst (Investment Banking)
Send PM
A square with area equal to 256 has its center at the origin [#permalink]
3
void wrote:
plz explain 2nd half of the problem....



Hi!

Solution:

Firstly, the area of the square=256, Thus, the side of the square=16.
Next we are said that the origin (0,0) is the centre i.e. all the sides are equidistant. Hence, the vertices of the square are (8,8), (-8,-8), (8,-8) & (-8,8)

Now, the second half of the question says f(x)=c\(x^3\)
Whenever you see a f(x) in a coordinate geometry question simply substitute f(x) with y
So, we get, y=c\(x^3\)
The question then says this function passes through opposite vertices of the square i.e. it passes diagonally from point (8,8)to (-8,-8) or from point (8,-8) to (-8,8)

Lets substitute the value of x &y to get c
Considering (8,8)
8=c*\(8^3\)
c=\(\frac{1}{64}\)
Similarly, when you consider (-8,-8) you get C as \(\frac{1}{64}\)
And when we substitute the other two values we get \( \frac{-1}{64 } \). As c is a positive value we can negate the other two values

Thus, C=\(\frac{1}{64}\)

Hope this helps
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 4418
Own Kudos [?]: 68 [0]
Given Kudos: 0
Send PM
Re: A square with area equal to 256 has its center at the origin [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne