Carcass wrote:
If the operation ∆ is defined by \(a∆b = \frac{(b-a)^2}{a^2}\) for all number a and b, and \(a ≠ 0\), then \(-1∆(1∆ -1) =\)
We want to find the value of -1∆(1∆ -1), so let's first deal with the part in brackets...
\(1∆-1 = \frac{((-1)-1 )^2}{ 1^2}= \frac{(-2)^2}{ 1^2}= \frac{4}{ 1}=4\)
So, -1∆(1∆ -1) = -1∆4
Now we need to find the value of -1∆4
\(-1∆4 = \frac{(4-(-1))^2}{(-1)^2}= \frac{5^2}{1}= \frac{25}{1}=25\)
Answer: 25
Cheers,
Brent
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Brent Hanneson - founder of Greenlight Test Prep