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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
any explanations?
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
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to make the ∛90x a positive integer; we need to simplify it with the least possible value of x(integer)
x = 300; ∛90x = 30
Similarly, to make √(y/75) a positive integer;
y = 75; √(y/75) = 1

x*y = 300*75 = 22500
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
Thanks!! How did you find x=300 though?
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
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fraise wrote:
Thanks!! How did you find x=300 though?


The goal here is to make cube_root(90x) an integer.
If we let x = 300, then 90x = 90(300) = 27,000

So, cube_root(90x) = cube_root(27,000) = 30 (since 30³ = 27,000)

Does that help?
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
Thanks Brent. Well, I just think that you can indeed know that 300 makes it work, but it was hard for me to figure out that it was the smallest integer... Although you can write 300=3*100 and with the 90 you'll end up with a power 3 on the 10...
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
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just write down the 90 in its prime factor form , which is 5x3x3x2.
therefore, we need x= 5x5x3x2x2 to make power 3 of all.
so, x=300,
and y= 75 (no prime factorization needed),
therefore, xy= 22500
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Re: If sqrt3 of 90x and sqrt of y/75 are positive integers, and [#permalink]
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