Let's let Car X's original position be the initial starting point.
So, when Car X is at the initial starting point, Car Y has already traveled 40 miles.
My
word equation involves the conditions when Car X
catches up to Car Y.
At that point, we can say:
Car X's TOTAL distance traveled =
Car Y's TOTAL distance traveled Car Y's total distance
Let V = Car Y's speed (our goal is to find the value of V)
From the time that Car X begins moving, Car Y drives for 2 2/3 hours (2 hours, 40 minutes).
So Car Y's total distance = (time)(speed) = (2 2/3)(V) + 40 milesCar X's total distance
We know that Car X is going 50% faster than Car Y. If Car Y's rate is V, then Car X's rate must be 1.5V
We also know that Car X travels for 2 2/3 hours.
So Car X's total distance = (time)(speed) = (2 2/3)(1.5V) miles
Simplify: (2 2/3)(1.5V) = (8/3)(3/2) = 4V We're now ready to write our algebraic equation.
Car X's total distance =
Car Y's total distance4V =
(2 2/3)(V) + 40 miles4/3V = 40
V = 40(3/4)
V = 30
Cheers,
Brent
_________________
Brent Hanneson - founder of Greenlight Test Prep