Write out the sequence:

1, –3, 4, 1, –3, 4

6th term is 4 even though 6 is divisible by 2. We divided by 3 because there are 3 different types of numbers in the list.

For example lets take the following repeating sequence:

2, 5, 7, 8, 9, 2, 5, 7, 8, 9, 2, 5, 7, 8, 9, .....

What is the 15th number? 9 remainder of(15/5)= 0

what is the 22nd number? 5 remainder of (22/5)= 2


So you can vizualize the problem as follows:

remainder 1	remainder 2	remainder 3	remainder 4	remainder 0	remainder 1	remainder 2	remainder 3	remainder 4	remainder 0
2	5	7	8	9	2	5	7	8	9

Does this help?