GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 25Crafting an Impactful Resume: Balancing Detail with Brevity
10:00 AM EDT
-10:30 AM EDT
Showcase your achievements through impactful storytelling! Get ready for an LIVE session on April 25, Learn how to craft compelling narratives on your resume that resonate with admission committees.
Apr 26Get a Top GRE Score with Target Test Prep
12:00 PM EDT
-01:00 PM EDT
The Target Test Prep course represents a quantum leap forward in GRE preparation, a radical reinterpretation of the way that students should study. In fact, more and more Target Test Prep students are scoring 329 and above on the GRE.
The integer k is equal to m^2 for some integer
[#permalink]
16 May 2021, 02:38
16 May 2021, 02:38
Expert Reply
00:00
Question Stats:
46% (01:31) correct
53% (01:17) wrong based on 13 sessions
Hide Show timer Statistics
The integer ๐ is equal to \(๐^2\) for some integer ๐. If ๐ is divisible by 20 and 24, what is the smallest possible positive value of ๐?
Show: :: OA
3600
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: The integer k is equal to m^2 for some integer
[#permalink]
16 May 2021, 03:05
16 May 2021, 03:05
1
Carcass wrote:
The integer ๐ is equal to \(๐^2\) for some integer ๐. If ๐ is divisible by 20 and 24, what is the smallest possible positive value of ๐?
Show: :: OA
3600
\(k = m^2\)
\(20 = (2^2)(5)\)
\(24 = (2^3)(3)\)
I. \(m^2\) is divisible by 20
i.e. \(m^2\) must have at-least two 2s and one 5
II. \(m^2\) is divisible by 24
i.e. \(m^2\) must have at-least three 2s and one 3
This means, \(m^2\) must have at-least three 2s, one 3 and one 5 in it!
Since, \(k\) is a perfect square here, each prime factor must have even power
i.e. \(k = (2^4)(3^2)(5^2) = 3600\)
Re: The integer k is equal to m^2 for some integer
[#permalink]
13 Aug 2021, 20:53
13 Aug 2021, 20:53
KarunMendiratta wrote:
Carcass wrote:
The integer ๐ is equal to \(๐^2\) for some integer ๐. If ๐ is divisible by 20 and 24, what is the smallest possible positive value of ๐?
Show: :: OA
3600
\(k = m^2\)
\(20 = (2^2)(5)\)
\(24 = (2^3)(3)\)
I. \(m^2\) is divisible by 20
i.e. \(m^2\) must have at-least two 2s and one 5
II. \(m^2\) is divisible by 24
i.e. \(m^2\) must have at-least three 2s and one 3
This means, \(m^2\) must have at-least three 2s, one 3 and one 5 in it!
Since, \(k\) is a perfect square here, each prime factor must have even power
i.e. \(k = (2^4)(3^2)(5^2) = 3600\)
am sorry to ask this , how can we confirm it as perfect square ? and one more question is why dont we can have (2^2)(3^2)(5^2)
