ExplanationThe total mixture contains three cups, so the second bowl must contain two cups.
This 2-cup bowl of nuts divided into even thirds consists of \(\frac{2}{3}\)cups peanuts, cups cashews, \(\frac{2}{3}\) and \(\frac{2}{3}\) cups almonds.
Combining this with the 1-cup mixture of \(\frac{1}{2}\) cup peanuts and \(\frac{1}{2}\) cup cashews results in \(\frac{7}{6}\) cups peanuts in a 3-cup mixture.
So, \(\frac{6}{3}=\frac{7}{18}\) of the new nut mixture is peanuts.
Hence \(\frac{7}{18}\) is correct.
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