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The remainder when 120 is divided by single-digit integer m
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26 Aug 2017, 02:24
26 Aug 2017, 02:24
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The remainder when 120 is divided by single-digit integer m is positive, as is the remainder when 120 is divided by single-digit integer n. If m > n, what is the remainder when 120 is divided by m – n?
enter your value
Show: :: OA
zero
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Re: The remainder when 120 is divided by single-digit integer m
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28 Aug 2017, 15:07
28 Aug 2017, 15:07
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Carcass wrote:
The remainder when 120 is divided by single-digit integer m is positive, as is the remainder when 120 is divided by single-digit integer n. If m > n, what is the remainder when 120 is divided by m – n?
enter your value
enter your value
Show: :: OA
zero
IMPORTANT: If k = 1, 2, 3, 4, 5, 6, or 8 then the remainder will be ZERO when we divide 120 by k
The only two (1-digit) values that DO leave a remainder are 7 and 9
So, it must be the case that m = 9 and n = 7
If m > n, what is the remainder when 120 is divided by m – n?
m = 9 and n = 7, so m - n = 9 - 7 = 2
When we divide 120 by 2, the remainder is 0
Answer:
Show: ::
0
Cheers,
Brent
General Discussion
Re: The remainder when 120 is divided by single-digit integer m
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09 Feb 2021, 02:33
09 Feb 2021, 02:33
1
Hi,
The remainder when 120 is divided by single-digit integer m is positive, as is the remainder when 120 is divided by single-digit integer n. If m > n, what is the remainder when 120 is divided by m – n?
It is really necessary to pay attention and understand to the highlighted part in the question. As the remainder is positive it cannot be zero because, zero is neither positive nor negative.
Thus the number which gives us a remainder zero while dividing the number by 120 should be ignored.
i.e. m and n cannot be 1, 2, 3, 4, 5, 6 & 8 as all of them are divisible to 120
Leaving us with 7 & 9. And as m>n
m=9; n=7
m-n=2
Leaving us with remainder zero.
Hope this helps!
The remainder when 120 is divided by single-digit integer m is positive, as is the remainder when 120 is divided by single-digit integer n. If m > n, what is the remainder when 120 is divided by m – n?
It is really necessary to pay attention and understand to the highlighted part in the question. As the remainder is positive it cannot be zero because, zero is neither positive nor negative.
Thus the number which gives us a remainder zero while dividing the number by 120 should be ignored.
i.e. m and n cannot be 1, 2, 3, 4, 5, 6 & 8 as all of them are divisible to 120
Leaving us with 7 & 9. And as m>n
m=9; n=7
m-n=2
Leaving us with remainder zero.
Hope this helps!
