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x=1/1+1/1+1/2
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24 Apr 2019, 00:59
24 Apr 2019, 00:59
Expert Reply
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Question Stats:
92% (00:30) correct
7% (00:48) wrong based on 151 sessions
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\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
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x=1/1+1/1+1/2
[#permalink]
24 Apr 2019, 10:10
24 Apr 2019, 10:10
2
Carcass wrote:
\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
x=1/1+1/1+1/2
[#permalink]
25 Jul 2019, 09:21
25 Jul 2019, 09:21
3
Hi Brent,
I really like your explanations.
As you mentioned in another post. We just need to see that in denominator we are adding something to 1, which makes the denominator greater than 1 and the overall fraction less than 1.
Hence, B>A.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
I really like your explanations.
As you mentioned in another post. We just need to see that in denominator we are adding something to 1, which makes the denominator greater than 1 and the overall fraction less than 1.
Hence, B>A.
GreenlightTestPrep wrote:
Carcass wrote:
\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
