GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 25Crafting an Impactful Resume: Balancing Detail with Brevity
10:00 AM EDT
-10:30 AM EDT
Showcase your achievements through impactful storytelling! Get ready for an LIVE session on April 25, Learn how to craft compelling narratives on your resume that resonate with admission committees.
Apr 26Get a Top GRE Score with Target Test Prep
12:00 PM EDT
-01:00 PM EDT
The Target Test Prep course represents a quantum leap forward in GRE preparation, a radical reinterpretation of the way that students should study. In fact, more and more Target Test Prep students are scoring 329 and above on the GRE.
y = x^2 - 16x + 64
[#permalink]
02 Jul 2019, 00:06
02 Jul 2019, 00:06
1
Expert Reply
2
Bookmarks
00:00
Question Stats:
56% (00:55) correct
43% (01:00) wrong based on 85 sessions
Hide Show timer Statistics
\(y = x^2 - 16x + 64\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The least value of y |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
y = x^2 - 16x + 64
[#permalink]
02 Jul 2019, 05:56
02 Jul 2019, 05:56
1
1
2
Bookmarks
Carcass wrote:
\(y = x^2 - 16x + 64\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The least value of y |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Given: \(y = x^2 - 16x + 64\)
Factor right side to get: \(y = (x-8)^2\)
If we SQUARE any number, the result will always be greater than or equal to zero.
In this case, we can minimize y by letting x = 8
If \(x = 8\), then \(y=(x-8)^2=(8-8)^2=(0)^2=0\)
We get:
QUANTITY A: 0
QUANTITY B: 0
Answer: C
Cheers,
Brent
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
y = x^2 - 16x + 64
[#permalink]
06 Feb 2021, 21:39
06 Feb 2021, 21:39
1
Carcass wrote:
\(y = x^2 - 16x + 64\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The least value of y |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
A Quadratic Function such as \(y = ax^2 + bx + c\) is a Parabola!
The lowest point on the parabola would be it's Y-coordinate of the vertex (when a>0)
X-coordinate of the vertex = -b/2a = 16/2 = 8
Y-coordinate of the vertex = \(8^2\) - (16 x 8) + 64 = 0
Hence, Option C
