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Re: p is the probability that a school’s hockey team wins today. [#permalink]
1
Another way to think about is that it never states that either of them could NOT be 0. It simply states that they both cannot be 0, so set one of them equal to 0 and you quickly realize that the Quantity B is going to be 0 while quantity A will be an actual number greater than 0.
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Re: p is the probability that a school’s hockey team wins today. [#permalink]
This question is more about algebra than probability, Since probability can't be > 1
we know number are in range 0-1
hence any number between 0 and 1 when multiplied by another number between 0 and 1 reduces in value so option A is correct.
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Re: p is the probability that a school’s hockey team wins today. [#permalink]
p+s = P(A U B)+P(A and B) = P(A U B)+p*s.
Since we do not have both equal zero at the same time, P(A U B) >0. Therefore, p+s>p*S
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Re: p is the probability that a schools hockey team wins today. [#permalink]
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