sandy wrote:
\(x>1\)
\(x,x^2,xy,xy^{-1},x^4,x^6\)
Quantity A |
Quantity B |
The mode of the numbers above when y = 4 |
The median of the numbers above when y =5 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 2
Question: 1
Page: 524
I don't like this question...
Given set: \({x,x^2,xy,xy^{-1},x^4,x^6}\)
If \(y = 4\), then the set becomes: \({x,x^2,4x,\frac{1}{4}x,x^4,x^6}\)
So, if x = 2, then the set becomes \({2,4,8,\frac{1}{2},16,64}\), in which case the mode is \(2,4,8,\frac{1}{2},16,64\)
Similarly, if \(y = 5\), then the set becomes: \(x,x^2,5x,\frac{1}{5}x,x^4,x^6\)
So, if x = 2, then the set becomes \(2,4,20,\frac{2}{5},16,64\), in which case the median is \(10\)
So we have:
QUANTITY A: \(2,4,8,\frac{1}{2},16,64\)
QUANTITY B: \(10\)
There's no way to compare these two quantities.
Answer: Bad question
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Brent Hanneson - founder of Greenlight Test Prep