arjunbir wrote:
KarunMendiratta sir can you please explain provide explanation?
thank you
\(7x^2\) has two different prime factors
This means \(x\) must have prime factors too
For example;
If \(x = 2\)
\(7(2)^2 = (7)(2)(2)\) has 2 different prime factors \(2\) and \(7\)
So, number of different prime factors of \(x\) is one wiz. \(2\)
But WAIT, what if \(x\) is a multiple of \(7\)??
For example;
If \(x = 14\)
\(7(14)^2 = (7)(14)(14) = (7)(7)(7)(2)(2)\) also has 2 different prime factors \(2\) and \(7\)
But the number of different prime factors of \(x\) is two wiz. \(2\) and \(7\)
Col. A: \(2\)
Col. B: \(1\)
Hence, option A
_________________
I hope this helps!
Regards:
Karun Mendiratta
Founder and Quant Trainer
Prepster Education, Delhi, Indiahttps://www.instagram.com/prepster_education/