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abcd is different from zero

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Carcass
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abcd is different from zero [#permalink] New post   03 Aug 2020, 14:50
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\(abcd \neq 0\)

\(ad > bc\)

\(bd < 0\)


Quantity A
Quantity B
\(\frac{b}{a}\)
\( \frac{d}{c} \)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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D
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Re: abcd is different from zero [#permalink] New post   04 Aug 2020, 05:07
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Nothing about a and c. They can be negative or positive because...
We are not sure about the exact signs of b and d...we just know they have opposite signs.
Answer: D
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Re: abcd is different from zero [#permalink] New post   29 Oct 2020, 02:14
3
Subtracting d/c on both the sides:
Quantity A:
b/a-d/c
Quantity B:
0

Taking LCM for Quantity A, we get: bc-ad/ac........................[1]

Also given that ad>bc
=> ad-bc>0 or bc-ad<0.................................[2]

comparing 1 and 2, we have no idea whether ac > 0 or ac <0

Quantity A could be >0 or <0
Quantity B is ZERO (as shown above)

Pick choice D
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Re: abcd is different from zero [#permalink] New post   25 May 2021, 23:14
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Carcass wrote:
\(abcd \neq 0\)

\(ad > bc\)

\(bd < 0\)


Quantity A
Quantity B
\(\frac{b}{a}\)
\( \frac{d}{c} \)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



After rearranging answer choice we get ad in one quantity and bc in another quantity, But we are clear said that ad > bc , Thus quantity B must be greater. Carcass sir!
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Re: abcd is different from zero [#permalink] New post   26 May 2021, 01:01
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kumarneupane4344 wrote:
Carcass wrote:
\(abcd \neq 0\)

\(ad > bc\)

\(bd < 0\)


Quantity A
Quantity B
\(\frac{b}{a}\)
\( \frac{d}{c} \)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



After rearranging answer choice we get ad in one quantity and bc in another quantity, But we are clear said that ad > bc , Thus quantity B must be greater. Carcass sir!



But you do not know the signs ....Sir
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Re: abcd is different from zero [#permalink] New post   02 Jul 2021, 03:01
kumarneupane4344 wrote:
Carcass wrote:
\(abcd \neq 0\)

\(ad > bc\)

\(bd < 0\)


Quantity A
Quantity B
\(\frac{b}{a}\)
\( \frac{d}{c} \)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



After rearranging answer choice we get ad in one quantity and bc in another quantity, But we are clear said that ad > bc , Thus quantity B must be greater. Carcass sir!



Hi there!

Lets try to solve it this way!

Give: ad>bc
bd<0 this means that either b or d should be negative

So if d is negative, and b is positive. a has to be negative (because ad>bc) and c has to be negative......(1)
If d is positive, and b is negative. a has to be positive and c has to be positive......(2)

Using 1
Qty A: b/a= negative/positive
Qty B: d/c=positive/negative


Using 2
Qty A: b/a= positive/negative
Qty B: d/c= negative/positive

Now as we don't have the value of a, b, c & d we do not know which is greater and which is lesser.

Thus D

Hope this helps!
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Re: abcd is different from zero [#permalink] New post   29 Sep 2021, 01:19
1
a b c d
+-++
-+--
-++-

Either b or d should be - but not both. Test for these cases with a table and you should get D in 2 mins
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