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6 < su < 8 -8 < ut < -6
[#permalink]
31 Dec 2021, 07:11
31 Dec 2021, 07:11
Expert Reply
1
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Question Stats:
86% (01:33) correct
13% (01:07) wrong based on 36 sessions
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\(6 < su < 8 \)
\(-8 < ut < -6 \)
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
\(-8 < ut < -6 \)
Quantity A |
Quantity B |
s |
t |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
6 < su < 8 -8 < ut < -6
[#permalink]
31 Dec 2021, 20:29
31 Dec 2021, 20:29
1
\(6 < su < 8\) & \(-8 < ut < -6\)
If \(u > 0\) then \(s > 0\) & \(t < 0\)
If \(u < 0\) then \(s < 0\) & \(t > 0\)
Answer \(D\)
If \(u > 0\) then \(s > 0\) & \(t < 0\)
If \(u < 0\) then \(s < 0\) & \(t > 0\)
Answer \(D\)
Re: 6 < su < 8 -8 < ut < -6
[#permalink]
14 Jan 2023, 04:14
14 Jan 2023, 04:14
Carcass can you give an official explanation?
what I think is, in the both the equation, if we cancel the common u, we are left with 6<s<8 & −8<t<−6
Now, s has to be positive and t should be negative (given the inequalities)
so, shouldn't s > t ?
what I think is, in the both the equation, if we cancel the common u, we are left with 6<s<8 & −8<t<−6
Now, s has to be positive and t should be negative (given the inequalities)
so, shouldn't s > t ?
