GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 25Crafting an Impactful Resume: Balancing Detail with Brevity
10:00 AM EDT
-10:30 AM EDT
Showcase your achievements through impactful storytelling! Get ready for an LIVE session on April 25, Learn how to craft compelling narratives on your resume that resonate with admission committees.
Apr 24Get an Extra 30% Off Target Test Prep Plans
08:00 PM EDT
-11:59 PM EDT
Grab 30% off any Target Test Prep GRE plan during our Flash Sale and join Brian and many other students who have used Target Test Prep to score high on the GRE. Just enter the coupon code FLASH30 at checkout to save big.
Apr 26Get a Top GRE Score with Target Test Prep
12:00 PM EDT
-01:00 PM EDT
The Target Test Prep course represents a quantum leap forward in GRE preparation, a radical reinterpretation of the way that students should study. In fact, more and more Target Test Prep students are scoring 329 and above on the GRE.
xyz > 0 and y>0
[#permalink]
14 Feb 2022, 06:00
14 Feb 2022, 06:00
Expert Reply
00:00
Question Stats:
70% (00:57) correct
29% (00:40) wrong based on 54 sessions
Hide Show timer Statistics
\(xyz > 0\) and \(y > 0\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
Quantity A |
Quantity B |
\(xy^2z^3 \) |
\(0\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
xyz > 0 and y>0
[#permalink]
14 Feb 2022, 06:30
14 Feb 2022, 06:30
2
3
Bookmarks
Carcass wrote:
\(xyz > 0\) and \(y > 0\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
Quantity A |
Quantity B |
\(xy^2z^3\) |
\(0\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
We can solve this question using matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: \(xy^2z^3\)
Quantity B: \(0\)
Since we are told \(y\) is POSITIVE, we can safely divide both quantities by \(y\) to get:
Quantity A: \(xyz^3\)
Quantity B: \(0\)
Since \(z^2\) must be POSITIVE, we can safely divide both quantities by \(z^2\) to get:
Quantity A: \(xyz\)
Quantity B: \(0\)
Since it's given that \(xyz > 0\), the correct answer is A
RELATED VIDEO
General Discussion
Re: xyz > 0 and y>0
[#permalink]
14 Feb 2022, 09:49
14 Feb 2022, 09:49
1
Carcass wrote:
\(xyz > 0\) and \(y > 0\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
Quantity A |
Quantity B |
\(xy^2z^3 0\) |
\(0\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer: A
Since y>0, xz must be >0 for statement to hold true. Now x & z can either be +ve or -ve together.
Case 1: When both x & z are +v : Ans is A
Cash 2: When booth x & z are -ve: In xy^2z^3 0, we can ignore y as it's +v and also squared. Z^3 will always be -ve as it's raised to odd power, so all in all both -ve will multiply and whole no. will become +ve
