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b<0
[#permalink]
01 Oct 2022, 10:15
01 Oct 2022, 10:15
Expert Reply
00:00
Question Stats:
46% (00:27) correct
53% (01:01) wrong based on 26 sessions
Hide Show timer Statistics
\(b<0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{b+1}{ 1 + \frac{1}{b}}\) |
\(b\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the Skill Builder Project
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GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
Re: b<0
[#permalink]
15 Oct 2022, 11:17
15 Oct 2022, 11:17
1
Expert Reply
\(b<0\)
Is just there to distract you
If you manipulate
\(\frac{b+1}{\frac{b+1}{b}}\)
\(\frac{b^2+b}{b+1}\)
\(\frac{b(b+1)}{b+1} =b\)
C is the answer
Is just there to distract you
If you manipulate
\(\frac{b+1}{\frac{b+1}{b}}\)
\(\frac{b^2+b}{b+1}\)
\(\frac{b(b+1)}{b+1} =b\)
C is the answer
b<0
[#permalink]
16 Oct 2022, 00:09
16 Oct 2022, 00:09
Carcass wrote:
\(b<0\)
Is just there to distract you
If you manipulate
\(\frac{b+1}{\frac{b+1}{b}}\)
\(\frac{b^2+b}{b+1}\)
\(\frac{b(b+1)}{b+1} =b\)
C is the answer
Is just there to distract you
If you manipulate
\(\frac{b+1}{\frac{b+1}{b}}\)
\(\frac{b^2+b}{b+1}\)
\(\frac{b(b+1)}{b+1} =b\)
C is the answer
Hello sir
Why substitution of number doesn’t work for this one?
Say b=-1 since b<0
Posted from my mobile device
