Last visit was: 23 Apr 2024, 11:24 It is currently 23 Apr 2024, 11:24

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 16 Feb 2017
Posts: 17
Own Kudos [?]: 8 [5]
Given Kudos: 0
Send PM
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4810
Own Kudos [?]: 10616 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11679 [0]
Given Kudos: 136
Send PM
avatar
Intern
Intern
Joined: 29 Mar 2017
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 0
Location: United States
WE:Engineering (Consulting)
Send PM
Re: if X>Y [#permalink]
One can also investigate intuitively without doing any calculation that fewer x's being in the mean average when x is greater will ALWAYS be greater when there are fewer comparative numbers.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11679 [0]
Given Kudos: 136
Send PM
Re: if X>Y [#permalink]
ryanmcgrawse wrote:
One can also investigate intuitively without doing any calculation that fewer x's being in the mean average when x is greater will ALWAYS be greater when there are fewer comparative numbers.


Sounds reasonable - I think :-)
Can you provide an example or two?

Cheers,
Brent
avatar
Intern
Intern
Joined: 29 Mar 2017
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 0
Location: United States
WE:Engineering (Consulting)
Send PM
Re: if X>Y [#permalink]
Greenlighttestprep - I suppose I'm not too helpful on the explanation. I just used reason, which Sandy clearly illustrated. Let's assume you have x > y and there is the mean of x,y for A and the mean of x,x,y for B, you'd get a similar answer. Essentially, more power is given to the higher number when the mean has a more substantial ratio between the higher and lower number. I don't have a mathematical proof, but I can put it together logically.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11679 [1]
Given Kudos: 136
Send PM
Re: if X>Y [#permalink]
1
ryanmcgrawse wrote:
Greenlighttestprep - I suppose I'm not too helpful on the explanation. I just used reason, which Sandy clearly illustrated. Let's assume you have x > y and there is the mean of x,y for A and the mean of x,x,y for B, you'd get a similar answer. Essentially, more power is given to the higher number when the mean has a more substantial ratio between the higher and lower number. I don't have a mathematical proof, but I can put it together logically.


Sounds perfect to me! Thanks for the clarification!

Cheers,
Brent
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 4411
Own Kudos [?]: 68 [0]
Given Kudos: 0
Send PM
Re: if X>Y [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne