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A box contains 20 marbles all of which are solid
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Updated on: 11 Dec 2019, 09:47
Updated on: 11 Dec 2019, 09:47
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Question Stats:
84% (00:40) correct
15% (00:37) wrong based on 103 sessions
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A box contains 20 marbles all of which are solid colored; 5 of the marbles are green and 10 of the marbles are red.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The probability that a marble selected at random form the box will be green |
The probability that a marble selected at random from the box will be neither red nor green |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: GRE Math Challenge #86- A box contains 20 marbles all of
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18 Aug 2016, 06:17
18 Aug 2016, 06:17
1
sandy wrote:
A box contains 20 marbles all of which are solid colored; 5 of the marbles are green and 10 of the marbles are fed.
Quantity A: The probability that a marble selected at random form the box will be green
Quantity B: The probability that a marble selected at random from the box will be neither red now green
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity A: The probability that a marble selected at random form the box will be green
Quantity B: The probability that a marble selected at random from the box will be neither red now green
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
in this for quantity A, the probability will be 5/20 = 1/4. when it comes to quantity B, the probability is found out using P(A)*P(B) = (5/20)*(10/20) = 1/8
so the answer is A
Re: GRE Math Challenge #86- A box contains 20 marbles all of
[#permalink]
18 Aug 2016, 11:36
18 Aug 2016, 11:36
1
I think both quantities are equal and answer is (C). This is my solution to this problem:
Let probability of selecting a green marble at random from the box is P(G) & probability of selecting a red marble at random from the box is P(R) & probability of selecting a marble at random from the box that is neither nor green is is P(neither G nor R)
P(G)*P(R) = 0, as both are mutually exclusive events.
Quantity A : P(G) = (5/20) =(1/4) ; B : P(neither G nor R) = 1 – (P(G)+P(R)) = 1 – ((5/20)+(10/20)) = 1/4
Let probability of selecting a green marble at random from the box is P(G) & probability of selecting a red marble at random from the box is P(R) & probability of selecting a marble at random from the box that is neither nor green is is P(neither G nor R)
P(G)*P(R) = 0, as both are mutually exclusive events.
Quantity A : P(G) = (5/20) =(1/4) ; B : P(neither G nor R) = 1 – (P(G)+P(R)) = 1 – ((5/20)+(10/20)) = 1/4
