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Re: 1/6 - (1/2)^2 + (-1/4)^2 [#permalink]
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Carcass wrote:

This question is part of GREPrepClub - The Questions Vault Project



Quantity A
Quantity B
\(\frac{1}{6}- (\frac{1}{2})^2 + (\frac{-1}{4})^2\)
\(\frac{1}{6}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Given:
QUANTITY A: \(\frac{1}{6}- (\frac{1}{2})^2 + (\frac{-1}{4})^2\)
QUANTITY B: \(\frac{1}{6}\)

Expand the two powers in Quantity A to get:
QUANTITY A: \(\frac{1}{6}- \frac{1}{4} + \frac{1}{16}\)
QUANTITY B: \(\frac{1}{6}\)

Rewrite the fractions in Quantity A with a common denominator of 48 to get:
QUANTITY A: \(\frac{8}{48}- \frac{12}{48} + \frac{3}{48}\)
QUANTITY B: \(\frac{1}{6}\)

Combine the fractions in Quantity A to get:
QUANTITY A: \(-\frac{1}{48}\)
QUANTITY B: \(\frac{1}{6}\)

Answer: B
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