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A cube of cheese is 3-inches high. The cheese is sliced twic
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29 Oct 2017, 02:12
29 Oct 2017, 02:12
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Question Stats:
46% (00:41) correct
53% (01:02) wrong based on 126 sessions
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A cube of cheese is 3-inches high. The cheese is sliced twice.
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Quantity A |
Quantity B |
Resulting surface area of all the slices of cheese |
90 square inches |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Re: A cube of cheese is 3-inches high. The cheese is sliced twic
[#permalink]
09 Apr 2018, 15:54
09 Apr 2018, 15:54
12
Expert Reply
You do not need to solve this question at all.
A cube of cheese is 3-inches high. The cheese is sliced twice. Nothing has been mentioned about how the cheese is sliced.
Inkedimages_LI.jpg [ 591.29 KiB | Viewed 10584 times ]
Take a look at the picture above. both cases satisfy the questions requirement however the area of the resultant solids are vastlz varying .
Imagine if you cut two really thin slices and rest of the bolck is intact then the area would be different from when the block is sliced from the middle.
This kind of question needs a bit of vizualization.
A cube of cheese is 3-inches high. The cheese is sliced twice. Nothing has been mentioned about how the cheese is sliced.
Attachment:
Inkedimages_LI.jpg [ 591.29 KiB | Viewed 10584 times ]
Take a look at the picture above. both cases satisfy the questions requirement however the area of the resultant solids are vastlz varying .
Imagine if you cut two really thin slices and rest of the bolck is intact then the area would be different from when the block is sliced from the middle.
This kind of question needs a bit of vizualization.
Re: A cube of cheese is 3-inches high. The cheese is sliced twic
[#permalink]
09 Apr 2018, 14:34
09 Apr 2018, 14:34
5
1
Let me try this one out - If the cube is sliced twice it will result in 3 cuboids -
Scenario 1: The cheese is sliced twice along length at 1 inches, the 3 cuboids formed will have length (l) = 1 inch, width(w) = 3 inches, height(h) = 3inches.
The area of surface Area of one of these cuboids = 2*(w*h) + 2*(h*l) + 2*(w*l) = 2*(3*3) + 2*(3*1) + 2*(3*1) = 30
Surface area of all 3 cuboids = 3 * 30 = 90
Scenario 2: The cheese is sliced first along length at 1.5 inches giving 2 equal cuboids now cut one of cuboids from width giving 2 more cuboids w = 1.5 inch, h = 3inches, l = 1.5 inch. In total 3 cuboids formed.
First cuboid will have length (l) =2 inch, width(w) = 3 inches, height(h) = 3inches. Second and Third Cuboid cuboid will have length (l) =0.5 inch, width(w) = 3 inches, height(h) = 3inches.
The area of surface Area of First cuboid = 2*(w*h) + 2*(h*l) + 2*(w*l) = 2*(3*3) + 2*(3*1.5) + 2*(3*1.5) = 26 inches
Surface area of second and third cuboids = 2*(1.5*3) + 2*(3*1.5) + 2*(1.5*1.5) = 22.5 inches
Total Surface Area of 3 cuboids 26 + 2*(22.5) = 71inches
Hence Answer D
However, this took a bit of time in trying out different scenarios.
Scenario 1: The cheese is sliced twice along length at 1 inches, the 3 cuboids formed will have length (l) = 1 inch, width(w) = 3 inches, height(h) = 3inches.
The area of surface Area of one of these cuboids = 2*(w*h) + 2*(h*l) + 2*(w*l) = 2*(3*3) + 2*(3*1) + 2*(3*1) = 30
Surface area of all 3 cuboids = 3 * 30 = 90
Scenario 2: The cheese is sliced first along length at 1.5 inches giving 2 equal cuboids now cut one of cuboids from width giving 2 more cuboids w = 1.5 inch, h = 3inches, l = 1.5 inch. In total 3 cuboids formed.
First cuboid will have length (l) =2 inch, width(w) = 3 inches, height(h) = 3inches. Second and Third Cuboid cuboid will have length (l) =0.5 inch, width(w) = 3 inches, height(h) = 3inches.
The area of surface Area of First cuboid = 2*(w*h) + 2*(h*l) + 2*(w*l) = 2*(3*3) + 2*(3*1.5) + 2*(3*1.5) = 26 inches
Surface area of second and third cuboids = 2*(1.5*3) + 2*(3*1.5) + 2*(1.5*1.5) = 22.5 inches
Total Surface Area of 3 cuboids 26 + 2*(22.5) = 71inches
Hence Answer D
However, this took a bit of time in trying out different scenarios.
