GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 25Crafting an Impactful Resume: Balancing Detail with Brevity
10:00 AM EDT
-10:30 AM EDT
Showcase your achievements through impactful storytelling! Get ready for an LIVE session on April 25, Learn how to craft compelling narratives on your resume that resonate with admission committees.
Apr 26Get a Top GRE Score with Target Test Prep
12:00 PM EDT
-01:00 PM EDT
The Target Test Prep course represents a quantum leap forward in GRE preparation, a radical reinterpretation of the way that students should study. In fact, more and more Target Test Prep students are scoring 329 and above on the GRE.
If a, b, and c are multiples of 3 such that a > b > c > 0, w
[#permalink]
12 Aug 2018, 16:08
12 Aug 2018, 16:08
Expert Reply
1
Bookmarks
00:00
Question Stats:
84% (00:53) correct
15% (00:39) wrong based on 82 sessions
Hide Show timer Statistics
If a, b, and c are multiples of 3 such that a > b > c > 0, which of the following values must be divisible by 3?
Indicate all such values.
A. a + b + c
B. a – b + c
C. \(\frac{abc}{9}\)
Indicate all such values.
A. a + b + c
B. a – b + c
C. \(\frac{abc}{9}\)
Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w
[#permalink]
17 Aug 2018, 16:00
17 Aug 2018, 16:00
4
Expert Reply
Explanation
Since a, b, and c are all multiples of 3, a = 3x, b = 3y, c = 3z, where x > y > z > 0 and all are integers.
Substitute these new expressions into the statements.
First statement: \(a + b + c = 3x + 3y + 3z = 3(x + y + z)\). Since (x + y + z) is an integer, this number must be divisible by 3.
Second statement: \(a - b + c = 3x - 3y + 3z = 3(x - y + z)\). Since (x + y + z) is an integer, this number must be divisible by 3.
Third statement:\(\frac{abc}{9}=\frac{3x \times 3y \times 3z}{9}=\frac{27xyz}{9}= 3xyz\). Since xyz is an integer, this number must be divisible by 3.
Since a, b, and c are all multiples of 3, a = 3x, b = 3y, c = 3z, where x > y > z > 0 and all are integers.
Substitute these new expressions into the statements.
First statement: \(a + b + c = 3x + 3y + 3z = 3(x + y + z)\). Since (x + y + z) is an integer, this number must be divisible by 3.
Second statement: \(a - b + c = 3x - 3y + 3z = 3(x - y + z)\). Since (x + y + z) is an integer, this number must be divisible by 3.
Third statement:\(\frac{abc}{9}=\frac{3x \times 3y \times 3z}{9}=\frac{27xyz}{9}= 3xyz\). Since xyz is an integer, this number must be divisible by 3.
Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w
[#permalink]
06 Jul 2019, 13:36
06 Jul 2019, 13:36
sandy wrote:
If a, b, and c are multiples of 3 such that a > b > c > 0, which of the following values must be divisible by 3?
Indicate all such values.
A. a + b + c
B. a – b + c
C. \(\frac{abc}{9}\)
Indicate all such values.
A. a + b + c
B. a – b + c
C. \(\frac{abc}{9}\)
There is a little bit problem with this type of question, like when you solve the question. and get two or three answer choices, and when you just put your answer in one case (A), then try to put the second answer in (B/C) but before this, the GRE Timer just stop when you click answer A. Need some Web coding to dynamic this. Thanks
