Carcass wrote:
If \(\frac{x}{y}>1\) and \(x+y<0\) , then which of the following must be true?
A. \(|x| >|y|\)
B. \(x<y\)
C. \(x>y\)
D. \(x^2>y^2\)
If \(\frac{x}{y} > 1\) then, \(x\) and \(y\) must be both +ve or both -ve
And If, \(x+y<0\) then, \(x\) and \(y\) must be both -ve
Now, Since \(x\) and \(y\) are both -ve, and \(\frac{x}{y} > 1\),
we can conclude that \(x < y\)
Lets take an example, \(x = -3\) and \(y = -2\)
A. \(|-3| >|-2|\) = YESB. \(x<y\) = YES (that's what we concluded)C. \(x>y\) = Can't be!D. \((-3)^2>(-2)^2\) = YESHence, options A, B and D
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I hope this helps!
Regards:
Karun Mendiratta
Founder and Quant Trainer
Prepster Education, Delhi, Indiahttps://www.instagram.com/prepster_education/