Re: PQ and RS are 2 mutually perpendicular chords intersecting at X. QX =
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13 Jul 2022, 07:40
To find SX= (PX * QX)/XR= 5 * 3 /2 = 7.5
To find the midpoint of chord PQ and RS,we have
Midpoint of PQ(M)=5+3=8/2=4
Midpoint of RS(N)=7.5+2=9.5/2=4.75
Now we have PM=QM=4 and SN=RN=4.75
OM=NX=RN-RX=4.75 - 2 =2.75
To find the radius which is OP=OQ
We use Pythagoras theorem,
OP=square root ( sqr(PM) +Sqr(OM))
=square root (4×4 + 7.75x7.75)
=square root(16+7.56)
Radius =square root(23.56)