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The expression x$y is defined as , where y ≠ 0. What is the
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27 Jul 2018, 07:02
27 Jul 2018, 07:02
Expert Reply
00:00
Question Stats:
94% (00:36) correct
5% (02:17) wrong based on 38 sessions
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The expression x$y is defined as \(\frac{x^2}{y}\), where y ≠ 0. What is the value of 9$(6$2)?
(A) \(\frac{1}{2}\)
(B) \(\frac{9}{4}\)
(C) \(\frac{9}{2}\)
(D) \(18\)
(E) \(108\)
(A) \(\frac{1}{2}\)
(B) \(\frac{9}{4}\)
(C) \(\frac{9}{2}\)
(D) \(18\)
(E) \(108\)
Re: The expression x$y is defined as , where y ≠ 0. What is the
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28 Jul 2018, 02:27
28 Jul 2018, 02:27
1
sandy wrote:
The expression x$y is defined as \(\frac{x^2}{y}\), where y ≠ 0. What is the value of 9$(6$2)?
(A) \(\frac{1}{2}\)
(B) \(\frac{9}{4}\)
(C) \(\frac{9}{2}\)
(D) \(18\)
(E) \(108\)
(A) \(\frac{1}{2}\)
(B) \(\frac{9}{4}\)
(C) \(\frac{9}{2}\)
(D) \(18\)
(E) \(108\)
Phase 1:
6$2 = \(\frac{6^2}{2}\)
= 18
Phase 2:
9$18 = \(\frac{9^2}{18}\)
= 81 / 18
= 9/2
The best answer is C.
Re: The expression x$y is defined as , where y ≠ 0. What is the
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12 Aug 2018, 04:57
12 Aug 2018, 04:57
Expert Reply
Explanation
This problem defines a function for the made-up symbol $. The order of operation rules (PEMDAS) stay the same even when the problem uses made-up symbols.
First, calculate the value of the expression in parentheses, \(6\$2\). Plug x = 6 and y = 2 into the function: \(\frac{6^2}{2}=\frac{36}{2}=18\).
Replace \(6\$2\) with 18 in the original expression to give 9$18. Again, plug x = 9 and y = 18 into the function:
\(9\$18=\frac{9^2}{18}=\frac{81}{18}=\frac{9}{2}\).
This problem defines a function for the made-up symbol $. The order of operation rules (PEMDAS) stay the same even when the problem uses made-up symbols.
First, calculate the value of the expression in parentheses, \(6\$2\). Plug x = 6 and y = 2 into the function: \(\frac{6^2}{2}=\frac{36}{2}=18\).
Replace \(6\$2\) with 18 in the original expression to give 9$18. Again, plug x = 9 and y = 18 into the function:
\(9\$18=\frac{9^2}{18}=\frac{81}{18}=\frac{9}{2}\).
