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Re: When the positive integer x is divided by 6, the remainder i [#permalink]
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Expert Reply
x could be 4, 10, 16, 22, 28, 34, 40

All answer choices but B are divisible for these numbers
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Re: When the positive integer x is divided by 6, the remainder i [#permalink]
I mean that if X=22
It mus be divisible by all the answer choices except B.
How did you conclude that we can take all the possibilities?
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Re: When the positive integer x is divided by 6, the remainder i [#permalink]
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When the positive integer x is divided by 6, the remainder is 4

Theory: Dividend = Divisor*Quotient + Remainder

x -> Dividend
6 -> Divisor
a -> Quotient (Assume)
4 -> Remainders
=> x = 6*a + 4 = 6a + 3 + 1 = 3*(2a + 1) + 1
=> \(\frac{x}{3}\) = \(\frac{3*(2a + 1)}{3}\) + \(\frac{1}{3}\) = 2a + 1 + \(\frac{1}{3}\)

=> \(\frac{x}{3}\) is NOT an integer

So, Answer will be B
Hope it helps!

Watch the following video to learn the Basics of Remainders

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Re: When the positive integer x is divided by 6, the remainder i [#permalink]
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There is another way to think about it:
x = 6*p + 4

Here p is the divisor and 4 the remainder.
If we divide the above by 3:
x/3 = 6*p/3 + 4/3

No matter what value of p, the expression 6*p/3 is evenly divided by 3 because of the 6. Therefore, the remaining term 4/3 will produce a non-integer.

We do not need to check any further. Choose B.
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