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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6,

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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink] New post   29 Aug 2018, 16:15
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.
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A
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink] New post   03 Sep 2018, 18:17
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(a+b+c+5+6)/5=6, so a+b+c+11=30, a+b+c=19.

a+b+c+13=32, average is (a+b+c+13)/4=32/4=8
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink] New post   04 Sep 2018, 08:54
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The answer is 8.
a+b+c+11 = 30
a+b+c = 19
a+b+c+13 = 32

32/4 = 8
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink] New post   26 Mar 2020, 14:46
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This is an example of how ETS will try to get you to combine variables for a mean and then forget that each is a separate value. a+b+c = 19... ok... a+b+c+13 = 19+13. In taking the mean here DIVIDE BY 4. Many will accidentally divide by 2 and end up answering wrong.
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink] New post   05 Aug 2022, 22:53
Theory

    ➡ Average = Sum of all the Values / Total Number of Values

The average (arithmetic mean) of a, b, c, 5, and 6 is 6

Average = \(\frac{Sum}{5}\) = \(\frac{a + b + c + 5 + 6 }{5}\) = \(\frac{a + b + c + 11}{5}\) = 6 (given)
a + b + c + 11 = 6*5 = 30
=> a + b + c = 30 - 11 = 19

The average of a, b, c, and 13

Average = \(\frac{Sum}{4}\) = \(\frac{a + b + c + 13 }{4}\) = \(\frac{19 + 13}{4}\) = \(\frac{32}{4}\) = 8

So, Answer will be A.
Hope it helps!

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