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In a plane, points P and Q are 20 inches apart. If point R i
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07 Nov 2019, 11:37
07 Nov 2019, 11:37
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Question Stats:
37% (02:30) correct
62% (01:28) wrong based on 90 sessions
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In a plane, points P and Q are 20 inches apart. If point R is randomly chosen from all the points in the plane that are 20 inches from P, what is the probability that R is closer to P than it is to Q?
A. \(0\)
B. \(\frac{1}{4}\)
C. \(\frac{1}{3}\)
D. \(\frac{1}{2}\)
E. \(\frac{2}{3}\)
A. \(0\)
B. \(\frac{1}{4}\)
C. \(\frac{1}{3}\)
D. \(\frac{1}{2}\)
E. \(\frac{2}{3}\)
Re: In a plane, points P and Q are 20 inches apart. If point R i
[#permalink]
12 May 2020, 13:36
12 May 2020, 13:36
Expert Reply
Locus of R is a circle, whose center is P and whose radius is 20 inches.
Distance of R from P is 20 inches
R is closer to P if R lies anywhere on the highlighted(Red) portion of the circle
Probability= 240/360=2/3
Distance of R from P is 20 inches
R is closer to P if R lies anywhere on the highlighted(Red) portion of the circle
Probability= 240/360=2/3
Re: In a plane, points P and Q are 20 inches apart. If point R i
[#permalink]
28 May 2020, 09:16
28 May 2020, 09:16
Where is the "highlighted(red)" portion of the circle. Not able to see it.
