Carcass wrote:
Let x, y, and z be non-zero numbers such that the average (arithmetic mean) of x and twice y is equal to the average (arithmetic mean) of y and twice z. What is the average (arithmetic mean) of x and y?
A. \(\frac{z}{2}\)
B. z
C. 2z
D. z-x
E. z-y
Kudos for the right answer and explanation
We know that: Average of x and 2y is equal to the average of y and 2z
\(=> (x + 2y)/2 = (y + 2z)/2\)
\(=> x + y = 2z\)
\(=> (x + y)/2 = z\)
=> Average of x and y is equal to z
Answer B
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