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When 140 is divided by positive integer k, the remainder is [#permalink]
Let's solve the problem using two methods

Method 1: Substitution (Substitute values of k from answer choices and check which one satisfies)

(A) 16
140 when divided by 16 gives 12 remainder ≠ (16-12 = 4) => FALSE

(B) 28
140 when divided by 28 gives 0 remainder ≠ (28-12 = 16) => FALSE

(C) 38
140 when divided by 38 gives 26 remainder = (38-12 = 26) => TRUE
In Test, we don't need to solve further. But I am solving to complete the solution.

(D) 48
140 when divided by 48 gives 44 remainder ≠ (48-12 = 36) => FALSE

(E) 51
140 when divided by 51 gives 38 remainder ≠ (51-12 = 39) => FALSE

So, Answer will be C

Method 2: Algebra (Substitute values of "a" and try to find the value of k)

When 140 is divided by positive integer k, the remainder is k - 12

Theory: Dividend = Divisor*Quotient + Remainder

140 -> Dividend
k -> Divisor
a -> Quotient (Assume)
k - 12 -> Remainders
=> 140 = k*a + k - 12
=> 152 = ak + 1

Let a = 1
=> 152 = k*1 + k = 2k
=> k = \(\frac{152}{2}\) = 76
But that is Not an answer choice given to us

Let a = 2
=> 152 = k*2 + k = 3k
=> k = \(\frac{152}{3}\) = 50.6 => Not an integer => NOT POSSIBLE
But that is Not an answer choice given to us

Let a = 3
=> 152 = k*3 + k = 4k
=> k = \(\frac{152}{4}\) =38

So, Answer will be C
Hope it helps!

Watch the following video to learn the Basics of Remainders

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