Hi phoenixio,
Well the mean is given to be 75. Let the integers be x,y,z, 90.
So we know that:
\(\frac{(x+y+z+90)}{4}\)= 75
\(x+y+z= 210\)
Lets say z is the smallest. So in order for z to be smallest possible x and y should be largest values possible.
Now we also know that \(x,y,z < 90\) (since 90 is the largest integer) and x,y,z, 90 are "different".
So x = 89 and y= 88 satisfy this criteria:
Hence \(z = 210 - 89 -88 =33\).
Cheers
PS: Source of the Que ?
_________________
SandyIf you found this post useful, please let me know by pressing the Kudos ButtonTry our free Online GRE Test