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A 2-pound mixture composed of 1/4 oil and 3/4 water is added to 3 poun
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13 Feb 2022, 05:15
13 Feb 2022, 05:15
Expert Reply
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Question Stats:
86% (01:24) correct
13% (01:42) wrong based on 15 sessions
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A 2-pound mixture composed of 1/4 oil and 3/4 water is added to 3 pounds of pure water. What percent of the resulting mixture is oil?
(A) 5%
(B) 8%
(C) 10%
(D) 15%
(E) 25%
(A) 5%
(B) 8%
(C) 10%
(D) 15%
(E) 25%
Re: A 2-pound mixture composed of 1/4 oil and 3/4 water is added to 3 poun
[#permalink]
13 Feb 2022, 10:47
13 Feb 2022, 10:47
1
Carcass wrote:
A 2-pound mixture composed of 1/4 oil and 3/4 water is added to 3 pounds of pure water. What percent of the resulting mixture is water?
(A) 5%
(B) 8%
(C) 10%
(D) 15%
(E) 25%
(A) 5%
(B) 8%
(C) 10%
(D) 15%
(E) 25%
I guessed C, can we have a official explanation
Original mix = 0.5p oil and 1.5p water, it's added to 3 p water, so water is now 4.5p with 0.5p oil in it.
% of resulting mix water = 1- (4.5/0.5) = 10%.
Re: A 2-pound mixture composed of 1/4 oil and 3/4 water is added to 3 poun
[#permalink]
13 Feb 2022, 11:42
13 Feb 2022, 11:42
Expert Reply
I do do not have the OE but the reasoning is perfect
We could also see the same result by simply translate word into math
what % of the new mixture, which is 5, is 0.5 % (the oil which is constant before and after)
\(\frac{x}{100} \times 5 = 0.5\)
x= 10%
We could also see the same result by simply translate word into math
what % of the new mixture, which is 5, is 0.5 % (the oil which is constant before and after)
\(\frac{x}{100} \times 5 = 0.5\)
x= 10%
