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Re: If a three-digit number formed with three nonzero digits is decreased [#permalink]
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OE

Quote:
Let: h = hundreds' digit t = tens' digit u = units' digit Then: the three-digit number =100h + 10t + u the two-digit number is 10h + u
Subtracting the latter from the former, the result is 90h + 10t = 10(9h + t). Since 9h + t has to be formed with nonzero values for h and t, the only impossible values for h and t is for the case of 180, where h = 2 and t = 0. All of the other cases give nonzero values for t. The answer is (D).
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If a three-digit number formed with three nonzero digits is decreased [#permalink]
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which of the following can not be the result?

The question is perfectly legit. I do not see any flaw.

Maybe BrushMyQuant could spends his two cents on this
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If a three-digit number formed with three nonzero digits is decreased [#permalink]
1
Carcass : Looks like all answers are possible

131 - 11 = 120
161 - 11 = 150
181 - 11 = 170
191 - 11 = 180
262 - 22 = 240
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Re: If a three-digit number formed with three nonzero digits is decreased [#permalink]
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Thank you sir for the feedback. Probably the question has a flaw

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