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Re: Frank is organizing a charity event in an effort to r [#permalink]
Tricky question
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Re: Frank is organizing a charity event in an effort to r [#permalink]
hugebigmac wrote:
draw two graphs. one for 20x^2 and one for 300x.
They will met at 15. After 15, 20x^2 will always larger than 300x.
The largest gap lies between 7 and 8. since there can only be integer number of guest, put 7 and 8 into the equation. we get 1120, which is below 1200.
Answer is E.


Why 20x^2 and not 20x? I am not following.

Can anyone give an alternative solution as well?
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Re: Frank is organizing a charity event in an effort to r [#permalink]
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Forget about fancy yet powerful ways of solution.

Your goal is when you are in front of a certain question is to approach it in the fastest and efficient way. Simple and straight. the clock is running. down to the business.

In this case, pick C as a first possible answer. From this is C is too high as a number you do know that the answer must be D or E. Or the other way around.


330-20(6)=180*6=1080 not enough

300-20(8)=140*8= 1120 not enough

E is the answer.

Of course, you do not need to perform all such calculations. It is pretty easy to see they are not enough
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Re: Frank is organizing a charity event in an effort to r [#permalink]
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QuantumWonder wrote:
hugebigmac wrote:
draw two graphs. one for 20x^2 and one for 300x.
They will met at 15. After 15, 20x^2 will always larger than 300x.
The largest gap lies between 7 and 8. since there can only be integer number of guest, put 7 and 8 into the equation. we get 1120, which is below 1200.
Answer is E.


Why 20x^2 and not 20x? I am not following.

Can anyone give an alternative solution as well?


Approach 1:

Each person will donate = \((300 - 20x)\)
Total Donation = \((300 - 20x)\) x \(x\) = \($1200\)


i.e. \(20x^2 -300x + 1200 = 0\)
Upon solving, you will get Imaginary roots, Hence you cannot raise the desired amount of \($1200\)
So, option E

Approach 2:
You can simply plug in the option choices, and you will notice even when \(x = 8\), the raised amount is \($1120\)
So we can go with option E
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Re: Frank is organizing a charity event in an effort to r [#permalink]
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