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In a group of 100 homeowners
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25 Sep 2017, 13:53
25 Sep 2017, 13:53
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Question Stats:
56% (01:55) correct
43% (01:08) wrong based on 62 sessions
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In a group of 100 homeowners, x homeowners had an alarm security system and y homeowners had deadbolt locks. If z homeowners had neither an alarm security system nor deadbolt locks, how many homeowners had both an alarm security system and deadbolt locks?
a) 100 – x – y – z
b) 100 – x – y + z
c) x – y – z + 100
d) x + y + z + 100
e) x + y + z – 100
a) 100 – x – y – z
b) 100 – x – y + z
c) x – y – z + 100
d) x + y + z + 100
e) x + y + z – 100
Re: In a group of 100 homeowners
[#permalink]
26 Sep 2017, 02:10
26 Sep 2017, 02:10
1
Expert Reply
\(X + Y - Both + Neither = 100\)
\(X + Y -B + Z = 100\)
\(X + Y + Z -100 = B\)
E is the winner.
Pretty straight questions.
\(X + Y -B + Z = 100\)
\(X + Y + Z -100 = B\)
E is the winner.
Pretty straight questions.
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Re: In a group of 100 homeowners
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16 May 2018, 09:24
16 May 2018, 09:24
1
Expert Reply
pranab01 wrote:
In a group of 100 homeowners, x homeowners had an alarm security system and y homeowners had deadbolt locks. If z homeowners had neither an alarm security system nor deadbolt locks, how many homeowners had both an alarm security system and deadbolt locks?
a) 100 – x – y – z
b) 100 – x – y + z
c) x – y – z + 100
d) x + y + z + 100
e) x + y + z – 100
a) 100 – x – y – z
b) 100 – x – y + z
c) x – y – z + 100
d) x + y + z + 100
e) x + y + z – 100
We can create the equation:
Total = alarm + deadbolt - both + neither
100 = x + y - both + z
both = x + y + z - 100
Answer: E
