Last visit was: 25 Apr 2024, 06:29 It is currently 25 Apr 2024, 06:29

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 13 Mar 2018
Posts: 13
Own Kudos [?]: 27 [5]
Given Kudos: 0
Send PM
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4810
Own Kudos [?]: 10616 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
avatar
Intern
Intern
Joined: 13 Mar 2018
Posts: 13
Own Kudos [?]: 27 [0]
Given Kudos: 0
Send PM
Retired Moderator
Joined: 07 Jan 2018
Posts: 739
Own Kudos [?]: 1373 [0]
Given Kudos: 93
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
2
For every hour sue has a lead of \(\frac{2miles}{hr}\) over Rob.
To get an exact 1 lap lead sue has to have total lead of \(10\) miles as the lap is 10 miles long
Hence \(\frac{10}{2} = 5\). Time that is required to put a one lap lead on Rob
option c
Target Test Prep Representative
Joined: 09 May 2016
Status:Head GRE Instructor
Affiliations: Target Test Prep
Posts: 180
Own Kudos [?]: 269 [3]
Given Kudos: 114
Location: United States
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
2
Expert Reply
1
Bookmarks
Shrija Roy wrote:
Running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour and Rob ran at a constant rate of 6 miles per hour. If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


When Sue completes exactly 1 more lap than Rob, she will have traveled exactly 10 miles more than Rob (since the loop is 10 miles long). We can let both of the times = t and create the equation:

8t = 6t + 10

2t = 10

t = 5

Answer: C
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11681 [0]
Given Kudos: 136
Send PM
Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
2
Shrija Roy wrote:
Running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour and Rob ran at a constant rate of 6 miles per hour. If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


1 lap = 10 miles
So, if Sue completes 1 lap more than Rob completes, then we know that Sue has traveled 10 miles more than Rob

So, let's start with a word equation:
(Sue's travel distance) = (Rob's travel distance) + 10 miles

Distance = (speed)(time)
We know each person's speed, but we don't know their travel times.
Let t = Sue's travel time
So, t = Rob's travel time also

Now take our word equation and plug in the necessary values:
8t = 6t + 10
Solve to get: t = 5

Answer: C
avatar
Intern
Intern
Joined: 13 Mar 2018
Posts: 13
Own Kudos [?]: 27 [0]
Given Kudos: 0
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
I still have not been able to understand why the time would taken the same for both Sue and Rob, could anybody kindly advise?
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11681 [0]
Given Kudos: 136
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
Shrija Roy wrote:
I still have not been able to understand why the time would taken the same for both Sue and Rob, could anybody kindly advise?


They both started running at the same time, and we stopped the clock (for both runners) once Sue lapped Rob.

Cheers,
Brent
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11681 [0]
Given Kudos: 136
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
1
Shrija Roy wrote:
Running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour and Rob ran at a constant rate of 6 miles per hour. If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


As I mention in the video below, we can often solve these kinds of problems using more than 1 approach.
So, instead of comparing distances (as I did above), let's compare times

Our word equation can be: Sue's travel time = Rob's travel time

Let x = the distance Rob traveled
We know that Sue traveled ONE LAP more than Rob traveled. Since 1 lap = 10 miles, we know that Sue traveled 10 miles MORE THAN Rob.
This means x + 10 = the distance Sue traveled

time = distance/speed
So, our word equation becomes: (x + 10)/8 = x/6
Cross multiply to get: 6(x + 10) = 8(x)
Expand to get: 6x + 60 = 8x
We get: 60 = 2x
So, x = 30

This means ROB traveled 30 miles (and it means SUE traveled 40 miles)

If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?
time = distance/speed
Let's use Rob's distance and speed to get: time = 30/6 = 5 hours

Answer: C

RELATED VIDEO FROM OUR COURSE
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 4418
Own Kudos [?]: 68 [0]
Given Kudos: 0
Send PM
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne