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Re: What is the average (arithmetic mean) number of televisions per househ [#permalink]
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The average or mean is

Sum of the data values (number of televisions) / 100 (the sum to add up of the single percentages)

See here for more https://gre.myprepclub.com/forum/gre-me ... tml#p82942

However, we do have the last value is 5 or >

back to your question: that sum is how you have to calculate the numerator of the fraction to reach our solution.

I hope this helps

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What is the average (arithmetic mean) number of televisions per househ [#permalink]
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AkmKawser wrote:
Hello sir, Can you please explain why you are multiplying the total number of houses each time?


When we are finding average then in the numerator we are finding the total number of televisions in each category by multiplying the number of households in that category * number of televisions in that category.

Let's take an example of number of households with 1 Television.

To find the total number of televisions in houses with 1 television each we need to find the total number of houses in that category * 1 (As each house has only 1 television).

Now, how do we find the number of houses with 1 television? It is given to us that that percentage is 8% of the total number of houses => 8% * Total Number of houses

Hope this clarifies your doubt.
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What is the average (arithmetic mean) number of televisions per househ [#permalink]
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Average = (Total Number of Houses *16% * 0 + Total Number of Houses *8% * 1 + Total Number of Houses *24% * 2 + Total Number of Houses *20% * 3 + Total Number of Houses *20% * 4 + Total Number of Houses *12% * 5 or more) / Total Number of Houses



Basically, I was referring to that Yellow highlighted portion. Why multiply with "Total Number of Houses" each time?

Shouldn't it be like this below?

Average = (16% * 0 + 8% * 1 + 24% * 2 + 20% * 3 + 20% * 4 + 12% * 5 or more) / Total Number of Houses

Originally posted by AkmKawser on 30 Sep 2022, 11:07.
Last edited by AkmKawser on 10 Oct 2022, 03:41, edited 2 times in total.
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Re: What is the average (arithmetic mean) number of televisions per househ [#permalink]
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AkmKawser wrote:
Average = (Total Number of Houses *16% * 0 + Total Number of Houses *8% * 1 + Total Number of Houses *24% * 2 + Total Number of Houses *20% * 3 + Total Number of Houses *20% * 4 + Total Number of Houses *12% * 5 or more) / Total Number of Houses



Basically, I was referring to that Yellow highlighted portion. Why multiply with "Total Number of Horses" each time?

Isn't it should be like this below?

Average = (16% * 0 + 8% * 1 + 24% * 2 + 20% * 3 + 20% * 4 + 12% * 5 or more) / Total Number of Houses


To get total number of houses with 0 Televisions you have to do 16% multiplied by number of houses. Lets understand using below example

Total number of students = 100
% of boys in class is 20%

If I ask you the actual number of boys then will we say 20% or 20% of Total

We will say 20% of Total = \(\frac{20}{100}\) * 100 = 20 boys

Hope this helps!
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Re: What is the average (arithmetic mean) number of televisions per househ [#permalink]
Hello from the GRE Prep Club BumpBot!

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