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(1+1/2)^2(1+1/3)^2(1+1/4)^2
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27 Mar 2023, 02:37
27 Mar 2023, 02:37
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Question Stats:
63% (01:45) correct
36% (01:43) wrong based on 11 sessions
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\((1+\frac{1}{2})^2(1+\frac{1}{3})^2(1+\frac{1}{4})^2.............(1+\frac{1}{10})^2= ?\)
9/100
4/121
9/21
1089/400
121/4
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
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\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE SEQUENCES
9/100
4/121
9/21
1089/400
121/4
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE SEQUENCES
(1+1/2)^2(1+1/3)^2(1+1/4)^2
[#permalink]
01 May 2023, 12:41
01 May 2023, 12:41
Expert Reply
OE
\((\frac{3}{2})^2(\frac{4}{3})^2(\frac{5}{4})^2...................(\frac{11}{10})^2\)
\(\frac{3^2}{2^2}* \frac{4^2}{3^2}\).............................\(.\frac{11^2}{10^2}=\frac{121}{4}\)
\((\frac{3}{2})^2(\frac{4}{3})^2(\frac{5}{4})^2...................(\frac{11}{10})^2\)
\(\frac{3^2}{2^2}* \frac{4^2}{3^2}\).............................\(.\frac{11^2}{10^2}=\frac{121}{4}\)
gmatclubot
(1+1/2)^2(1+1/3)^2(1+1/4)^2 [#permalink]
01 May 2023, 12:41
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