Re: 22 percent of x
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18 Jan 2026, 09:43
1. Express the Quantities
- Quantity A: $22 %$ of $x$ is $\(0.22 x\)$.
- Quantity B: $\(\frac{2}{9}\)$ of $x$ can be converted to a decimal. Dividing 2 by 9 gives:
$$
\(2 \div 9=0.2222 \ldots\)
$$
So, Quantity B is approximately $\(0.222 x\)$.
2. Compare the coefficients
If we compare the numbers 0.22 and $0.222 \ldots$, we see that:
$$
\(0.2222 \ldots>0.22\)
$$
3. Consider the value of $x$
In Quantitative Comparison questions, unless a variable is defined (e.g., "where $x>0$ "), we must consider all types of numbers (positive, negative, and zero).
- If $x$ is positive (e.g., $x=100$ ):
- Quantity A: $\(0.22(100)=22\)$
- Quantity B: $\(0.222 \ldots(100)=22.22\)$
- Result: Quantity B is greater.
- If $x$ is zero ( $x=0$ ):
- Quantity A: 0
- Quantity B: 0
- Result: The quantities are equal.
- If $x$ is negative (e.g., $x=-100$ ):
- Quantity A: - 22
- Quantity B: - 22.22
- Result: Quantity $A$ is greater (since -22 is to the right of -22.22 on the number line).
Conclusion
Because the relationship between Quantity A and Quantity B changes depending on whether $x$ is positive, negative, or zero, we cannot determine a single consistent relationship.
The relationship cannot be determined from the information given.