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|2x 3| < 8, where x is an integer. What is the number of possible va
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30 Aug 2024, 03:17
30 Aug 2024, 03:17
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Question Stats:
85% (01:38) correct
14% (01:05) wrong based on 14 sessions
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\(|2x – 3| < 8\), where x is an integer. What is the number of possible values of ‘x’ that satisfy the given inequality?
A. 2
B. 4
C. 6
D. 8
E. 10
A. 2
B. 4
C. 6
D. 8
E. 10
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Re: |2x 3| < 8, where x is an integer. What is the number of possible va
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30 Aug 2024, 10:10
30 Aug 2024, 10:10
Given, |2x-3| < 8, we can write: -8 < 2x-3 < 8
Simplifying, -2.5 < x < 5.5
Since x is an integer, the possible values of x, in ascending order, is: {-2,-1,0,1,2,3,4,5}. So, there are 8 values of x that satisfy the inequality.
Hence, D is correct.
Simplifying, -2.5 < x < 5.5
Since x is an integer, the possible values of x, in ascending order, is: {-2,-1,0,1,2,3,4,5}. So, there are 8 values of x that satisfy the inequality.
Hence, D is correct.
gmatclubot
Re: |2x 3| < 8, where x is an integer. What is the number of possible va [#permalink]
30 Aug 2024, 10:10
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