hi when you see this, can we assume that when t is greater than s, then t > s. Or with this type of question, we cannot just insert random number?

Dude, are you crazy? Insert 100 into s, multiply by 4% you get 4. Now 4/0.03 is equal to 133.33...

4 * s = 3 * t for the RHS to be equal to the LHS isn't it obvious that t must be greater than s?

You guys are correct! \(s<t\)

\(4s=3t\) or \(\frac{4}{3}s=t\).

I have modified the explanation above.

Thanks and Regards,

If we put random numbers in s and t the answer would be D. By solving it via Algebraic method "t" is greater but by testing numbers it is not. Any comment on this please?

cant this question have option d as its answer choice ?
as after solving we get 4s =3t , and s and t both are >0
so if i take dummy data for s=2 and t-4 we get B is greater
and if take s =3 and t=4 we get both equal ?

Let's think that,

4s = 3t

or, \(\frac{s}{t} = \frac{3}{4}\)

If s is 3, then t is 4, again s is 9 then t is 12, therefore, t is always greater than s

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